A triangular plane ABC has vertices at A(10,20,30), B(50,15,25), C(30,45,40). Find perpendicular distance from point P(40,30,35) to this plane.

Draw projections of triangle ABC
Plot point P in both views
Find edge view of plane ABC by auxiliary projection
In edge view, plane appears as a line
Draw perpendicular from P to this edge view line
This perpendicular distance is the true shortest distance
Measure and verify using formula: d = |ax₀ + by₀ + cz₀ + d| / √(a² + b² + c²)