A square lamina ABCD of 45mm side has corner A on HP and diagonal AC perpendicular to HP and inclined at 40° to VP. Draw its projections.

Since AC is perpendicular to HP, in TV it appears as a point
In FV, AC makes 40° with XY, with A on XY
Diagonal length = 45√2 = 63.64mm
Points B and D are equidistant from AC and perpendicular to it
Distance of B,D from AC = side/√2 = 31.82mm
Complete projections with all four corners